If we divide 180 into two parts such that second part is 12 more than the twice of the first part, then the two parts are

Options

A. 56, 124
B. 54, 126
C. 52, 128
D. 50, 130

Explanation

To solve the problem of dividing 180 into two parts where the second part is 12 more than twice the first part, we can follow these steps:

### Step 1: Define the Variables
Let the first part be \( x \). Then, according to the problem, the second part can be expressed as \( 12 + 2x \).

### Step 2: Set Up the Equation
Since the total of the two parts is 180, we can write the equation:
\[ x + (12 + 2x) = 180 \]

### Step 3: Simplify the Equation
Combine like terms:
\[ x + 12 + 2x = 180 \]
This simplifies to:
\[ 3x + 12 = 180 \]

### Step 4: Isolate the Variable
Subtract 12 from both sides to isolate the term with \( x \):
\[ 3x = 180 - 12 \]
\[ 3x = 168 \]

### Step 5: Solve for \( x \)
Now, divide both sides by 3 to find \( x \):
\[ x = \frac{168}{3} \]
\[ x = 56 \]

### Step 6: Find the Second Part
Now that we have the first part, we can find the second part using the expression we defined earlier:
\[ \text{Second part} = 12 + 2x = 12 + 2(56) \]
Calculating this gives:
\[ = 12 + 112 = 124 \]

### Conclusion
Thus, the two parts are:
- First part: \( 56 \)
- Second part: \( 124 \)

### Final Answer
The two parts are 56 and 124.

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