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If log(6)x + 2log(36)x + 3log(216)x = 9 ...

If `log_(6)x + 2log_(36)x + 3log_(216)x = 9` then x = ______

A

6

B

36

C

216

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`log_(6)x+ 2log_(36) + 3log_(216)x = 19`
` Rightarrow log_(6)x + log_(6)x + log_(6)x =9`
` Rightarrow 3 log_(6)x = 9 Rightarrow log_(6)x = 3`
` Rightarrow x= 6^(3)`
` thereforex= 216`
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