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Find the area of the square whose one pa...

Find the area of the square whose one pair of opposite vertices are (2,-3) and (4,5).

Text Solution

Verified by Experts

Let the given vertices be A (2, -3) and C(4,5) .
Length of AC = `sqrt((4-2)^(2) +(5+3)^(2))`
= `sqrt(68)` units
`therefore` Area of the square = `(AC^(2))/(2) = ((sqrt(68))^(2))/(2) = 34` sq. units
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