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Find the number whose 30% is 36...

Find the number whose 30% is 36

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Let the number be x
Given that 30% of the number is 36.
`rArr 30% " of " x=36`
`rArr (30)/(100)xx x=36`
`rArr x= (36xx100)/(30) rArr x=120`
`:. `The required number is 120
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