At a certain pressure , the volume occupied by a given mass of a gas is 10 L at `0^(@) C`, calculate the volume occupied by the gas at `91^(@) C` at the same pressure.

Explanation

`{:("Initial condition",,"Final condition"),(V_(1) = 10 L,,V_(2) = ?),(T_(1) = 273 K,,T_(2) = (273 + 91)K=364 K):}`
According to Charles' law,`V_(1)/T_(1) = V_(2)/T_(2)`
` rArr 10/(273) = V_(2)/(364) rArr V_(2) = (10 xx 364)/(273) = 13.33 L`