Specific grabvity of 84% (w/w) pure `HNO_(3)` is 1.54. What volume of `HNO_(3)` is required to prepare one litre of 0.5 M `HNO_(3)` solutions?

Explanation

Specific gravity of `HNO_(3) = 1.54`
`M=w/"GMM"xx1000/V rArr0.5 = x/63 xx1000/1000 rArr x = 31.5`g
`31.5" g of "NHO_(3)` is present in 1 L of solution.
84 g is present in 100 g of solution
31.5 g is present in ? g of solution
` = (31.5 xx 100)/84 = 37.5` g
`"Density"="weight"//"volume"rArr1.54 =37.5//"volume" rArr V = 37.5//1.54 = 24.35` m L
`V_(1)M_(1) = V_(2)M_(2)" "24.35`m L of given` NHO_(3)` is required.