Home
Class 10
CHEMISTRY
Empirical formula of a compound is CH(3)...

Empirical formula of a compound is `CH_(3)N`. If the empieical formula weight is equal to one-fourth of its vapour density, find out the molecular formula of the compound.

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT, STOICHIOMETRY AND BEHAVIOUR OF GASES

    PEARSON IIT JEE FOUNDATION|Exercise Essay Type Questions|2 Videos
  • MOLE CONCEPT, STOICHIOMETRY AND BEHAVIOUR OF GASES

    PEARSON IIT JEE FOUNDATION|Exercise Level 1 (True or False|5 Videos
  • MOLE CONCEPT, STOICHIOMETRY AND BEHAVIOUR OF GASES

    PEARSON IIT JEE FOUNDATION|Exercise Very Short Answer Type Questions|29 Videos
  • METALLURGY

    PEARSON IIT JEE FOUNDATION|Exercise LEVEL 3|10 Videos
  • PERIODIC TABLE

    PEARSON IIT JEE FOUNDATION|Exercise LEVEL 3 APPLICATION-BASED QUESTIONS|5 Videos

Similar Questions

Explore conceptually related problems

The empirical formula of an organic compound is CH_(2)O . Its vapour density is 45. The molecular formula of the compound is

The empirical formula of a compound is CH_2O and its vapour density is 30. The molecular formula of the compound is:

Define empirical formula of a compound.

The empirical formula of compound is CH_(2)O .Its vapour density is 60 . The molecular formula of the compound is

The empirical formula of a compound is CH_(2)O .If the vapour density is 60, what would be the molecular formula of the compound?

Empirical formula of compound is CH_(2)O .If its molecular weight is 180 then the molecular formula of the compound is