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The ratio of the gram atomic weight of n...

The ratio of the gram atomic weight of nitrogen and oxygen is __________ .

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To find the ratio of the gram atomic weight of nitrogen and oxygen, we can follow these steps: ### Step 1: Understand the Concept of Gram Atomic Weight The gram atomic weight (or atomic mass) of an element is the mass of one mole of that element expressed in grams. For nitrogen (N) and oxygen (O), we need to know their atomic weights. ### Step 2: Determine the Atomic Weights - The atomic weight of nitrogen (N) is approximately 14 g/mol. - The atomic weight of oxygen (O) is approximately 16 g/mol. ### Step 3: Calculate the Gram Atomic Weights for Diatomic Molecules Since nitrogen and oxygen exist as diatomic molecules (N₂ and O₂), we need to multiply their atomic weights by 2: - For nitrogen (N₂): \[ \text{Gram atomic weight of } N_2 = 14 \, \text{g/mol} \times 2 = 28 \, \text{g/mol} \] - For oxygen (O₂): \[ \text{Gram atomic weight of } O_2 = 16 \, \text{g/mol} \times 2 = 32 \, \text{g/mol} \] ### Step 4: Set Up the Ratio Now, we can set up the ratio of the gram atomic weight of nitrogen to that of oxygen: \[ \text{Ratio} = \frac{\text{Gram atomic weight of } N_2}{\text{Gram atomic weight of } O_2} = \frac{28}{32} \] ### Step 5: Simplify the Ratio To simplify the ratio \( \frac{28}{32} \): - Divide both the numerator and the denominator by 4: \[ \frac{28 \div 4}{32 \div 4} = \frac{7}{8} \] ### Final Answer The ratio of the gram atomic weight of nitrogen to oxygen is: \[ \text{Ratio} = 7:8 \] ---
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