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Mole fraction of NaOH in an aqueous solu...

Mole fraction of NaOH in an aqueous solution is 0.3. Mole fraction of water is __________ .

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To find the mole fraction of water in an aqueous solution where the mole fraction of NaOH is given as 0.3, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Mole Fraction**: - The mole fraction of a component in a solution is defined as the ratio of the number of moles of that component to the total number of moles of all components in the solution. - The sum of the mole fractions of all components in a solution is always equal to 1. 2. **Identify Components**: - In this case, we have two components: NaOH (solute) and water (solvent). - Given: Mole fraction of NaOH (X_NaOH) = 0.3. 3. **Use the Mole Fraction Relationship**: - According to the mole fraction relationship: \[ X_{NaOH} + X_{water} = 1 \] - Where \(X_{water}\) is the mole fraction of water. 4. **Substituting the Known Value**: - Substitute the value of the mole fraction of NaOH into the equation: \[ 0.3 + X_{water} = 1 \] 5. **Solving for Mole Fraction of Water**: - Rearranging the equation to find \(X_{water}\): \[ X_{water} = 1 - 0.3 \] - Calculate: \[ X_{water} = 0.7 \] 6. **Conclusion**: - Therefore, the mole fraction of water in the solution is 0.7. ### Final Answer: The mole fraction of water is **0.7**. ---
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