In a `2.5` L flask at `27^(@)C` temperature, the pressure of a gas was found to be 8 atm. If ` 41 xx 10^(23)` molecules of the same gas are introduced into the container, the temperature changed to `T_(2)`. The pressure of gas is found to be 10 atm. Find out the value of `T_(2)`.

Options

A. 253 K
B. 347 K
C. 230 K
D. 370 K

Explanation

`6.023 xx 10^(23)` molecules correspond to 1 mole ` 2.41 xx 10^(23) ` molecules correspond to ?
` = (2.41 xx 10^(23) ) / (6.023 xx 10^(23)) = 0.4` moles
Case (i)
`._(1)V_(1) = n_(1).R_(1)." "T_(1)`
` 8.(2.5) = n_(1)(0.08).(300)`
`n_(1) = (8(2.5))/((0.08)(300))`
` n_(1) = 0.833` moles
Total moles, `n_(2) = 0.833 + 0.4`
` n_(2) = 1.233`
Case (ii)
` P_(2)V_(2) = n_(2)R T_(2)`
` 10(2.5) = 1.233 (0.08). T_(2)`
`T_(2) = 253.4` K