The molecular mass of a salt of oxyacid of chlorine of a divalent metal, which contains more number of oxygen atoms than its corresponding `-ic' acid is 239. What will be the molecular masses of its
(a) phosphate (b) iodide
(c ) bisulphate be?

Explanation

The formula of perchlorate of a divalent metal M is `M(ClO_(4))_(2)`.
Molecular mass of `M(ClO_(4))_(2) ` is 239.
Let x be the atomic mass of bivalent metal.
`:. X + 2[35.5 + 64] = 239 rArr x = 40`
`:.` The element is calcium.
(a) The formula of its phosphate is `Ca_(3)(PO_(4))_(2)`.
`:.` Its molecular mass is `(3 xx 40)+2[31+64] = 310`
(b) The formula of its iodide is `CaI_(2)`.
`:.` Its molecular mass is `40+(2 xx 127) = 294`
(c ) The formula of bisulphate is `Ca(HSO_(4))_(2)`
`:.` Its molecular mass is ` 40 +2[1+32+64] = 234`