`f^(prime)(x)=phi(x)` and `phi^(prime)(x)=f(x)` for all x.Also,f(3)=5 and `f^(prime)(3)=4`. Then the value of `[f(10)]^2-[phi(10)]^2` is _____

f^(prime)(x)=varphi^(prime)(x)=f(x) for all xdot Also, f(3)=5a n df^(prime)(3)=4. Then the value of [f(10)]^2 - [ varphi(10)]^2 is _____

f^(prime)(x)=varphi^(prime)(x)=f(x) for all xdot Also, f(3)=5a n df^(prime)(3)=4. Then the value of [f(10)]^2 − [ϕ(10)]^2is _____

f'(x)=phi(x) and phi'(x)=f(x) for all x.Also,f(3)=5 and f'(3)=4. Then the value of [f(10)]^(2)-[phi(10)]^(2) is

If function f satisfies the relation f(x)*f^(prime)(-x)=f(-x)*f^(prime)(x) for all x ,and f(0)=3, and if f(3)=3, then the value of f(-3) is ______________

If function f satisfies the relation f(x)*f^(prime)(-x)=f(-x)*f^(prime)(x) for all x ,and f(0)=3, and if f(3)=3, then the value of f(-3) is ______________

If f^(prime)(x)=asinx+bcosx and f^(prime)(0)=4,f(0)=3,f(pi/2)=5 . Find f(x).

If function f satisfies the relation f(x)*f^(prime)(-x)=f(-x)*f^(prime)(x)for a l lx ,a n df(0)=3,a n dif f(3)=3, then the value of f(-3) is ______________

If f^(prime)(x)=asinx+bcosx and f^(prime)(0)=4,\ \ f(0)=3,\ \ f(pi/2)=5 , find f(x) .

The function f: RvecR satisfies f(x^2)dotf^(x)=f^(prime)(x)dotf^(prime)(x^2) for all real xdot Given that f(1)=1 and f^(1)=8 , then the value of f^(prime)(1)+f^(1) is 2 b. 4 c. 6 d. 8