int((3sin theta-2)cos theta)/(5-cos^(2)-4sin theta)

Find :int((3sin theta-2)cos theta)/(5-cos^(2)theta-4sin theta)dth eta theta

int(2sin2 theta-cos theta)/(6-cos^(2)theta-4sin theta)d theta

The maximum value of the expression (1)/(sin^(2)theta+3sin theta cos theta+5cos^(2)theta)

If 3sin theta =2 cos theta , then (4sin theta - cos theta)/(4cos theta+sin theta) is equal to :

If 3 sin theta=2 cos theta , then 3 sin theta=2 cos theta , then (4 sin theta-cos theta)/(4 cos theta+sin theta) is equal to: यदि 3 sin theta=2 cos theta है, तो 3 sin theta=2 cos theta , then (4 sin theta-cos theta)/(4 cos theta+sin theta) का मान क्या होगा ?

int((sin theta-cos theta)d theta)/((sin theta+cos theta)sqrt(sin^(2) theta cos^(2)theta+sin theta cos theta))

int(d theta)/((sin theta-2cos theta)(2sin theta+cos theta))=

The maximum value of the expression (1)/(sin^(2)theta+3sin theta cos theta+5cos^(2)theta) is

The maximum vale of the expression (1)/(sin^(2)theta+3sin theta cos theta+5cos^(2)theta) is

The maximum value of the expression (1)/(sin^(2)theta+3sin theta cos theta+5cos^(2)theta) is