`cos^3 2theta+3cos2theta=4(cos^6theta-sin^6 theta)`

cos^(3)2 theta+3cos2 theta=4(cos^(6)theta-sin^(6)theta)

What is the value of [(cos^3 2 theta+ 3 cos 2 theta)div (cos^6 theta- sin^6 theta)] ? [(cos^3 2 theta+ 3 cos 2 theta)div (cos^6 theta- sin^6 theta)] का मान क्या है?

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

If theta=7.5^(@) Find the value of quad sin8 theta*cos theta-sin6 theta cos3 thetacos2 theta*cos theta-sin3 theta*sin4 theta

The value of (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) is (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) का मान है:

The value of (cos^6 theta+sin^6 theta+ 3sin^2 theta cos^2 theta)/(cosec theta sec theta(sin theta+cos theta-1)(sin theta+cos theta+1)) is : (cos^6 theta+sin^6 theta+ 3sin^2 theta cos^2 theta)/(cosec theta sec theta(sin theta+cos theta-1)(sin theta+cos theta+1)) का मान ज्ञात कीजिए?

The value of sin^(8)theta+cos^(8)theta+sin^(6)theta cos^(2)theta+3sin^(4)theta cos^(2)theta+cos^(6)theta sin^(2)theta+3sin^(2)thetacos^(4)theta is equal to

The value of sin^(8)theta+cos^(8)theta+sin^(6)theta cos^(2)theta+3sin^(4)theta cos^(2)theta+cos^(6)theta sin^(2)theta+3sin^(2)thetacos^(4)theta is equal to

int(2sin2 theta-cos theta)/(6-cos^(2)theta-4sin theta)d theta

If sintheta+sin^2theta=1, then prove that cos^(12)theta+3cos^(10)theta+3cos^8theta+cos^6theta-1=0 Given that sintheta=1-sin^2theta=1-sin^2theta=cos^2theta