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Calculate the binding energy per nucleon...

Calculate the binding energy per nucleon of `._(20)Ca^(40)` nucleus. Mass of `(._(20)Ca^(40)) = 39.962591 am u`.

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Calculate the binding energy per nucleon of "_20Ca^40 nucleus. Given mass of "_20Ca^40 nucleus = 39.962589 a.m.u., mass of proton = 1.007825 a.m.u., mass of neutron = 1.008665 a.m.u. and 1 a.m.u. = 931.5 MeV.

Calculate the binding energy per nucleon of ._20Ca^(40) nucleus. Given m ._20Ca^(40)=39.962589u , M_(p) =1.007825u and M_(n)=1.008665 u and Take 1u=931MeV .

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u, mass of a proton = 1.007825 u,, mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV.

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u , mass of proton = 1.007825 u . Mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV .

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u , mass of proton = 1.007825 u . Mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV .