Find `("lim")_(x->1^+)1/(x-1)dot`

Find : ("lim")_(x->1)[x]

Find : ("lim")_(x->-5//2)\ [x]dot

Evaluate(i) (lim)_(x->1)(x^(15)-1)/(x^(10)-1) (ii) (lim)_(x->0)(sqrt(1+x)-1)/x

Evaluate: ("Lim")_(x->1)(x^x-x)/(x-1-lnx)

If ("lim")_(x->a)[f(x)+g(x)]=2a n d ("lim")_(x->a)[f(x)-g(x)]=1, then find the value of ("lim")_(x->a)f(x)g(x)dot

Find Lim_(x to 1^+) (1/(x-1)) = ?

Evaluate (i) (lim)_(x""->1)(x^(15)-1)/(x^(10)-1) (ii) (lim)_(x""->0)(sqrt(1+x)-1)/x

Evaluate: ("lim")_(x->oo)[x(a^(1/x)-1)], a >1

Evaluate the following lim_(xto1) (x^3 -1)/(x-1)

Find lim_(xto-1)(x^(5)+1)/(x^(3)+1)