" Q."4" The number of electrons required to deposit "1g" atom of Al (at mass "=27" ) from a a solution of "AlCl_(3)" are ? (N=Avogadro "

The number of electrons required to deposit 1 g atom of Al(at. Wt.=27) from a solution of AlCI_3 are :

The number of electrons required to deposit 1 gram atom of aluminium (at wt = 27) from a solution of AlCl_3 will be ?

Calculate the number of electrons required to deposit 41.5 g of Al

The number of electrons required to deposit 1 g atom of aluminium (At. Wt. = 27) from a solution of aluminium chloride will be (where N is Avogadro's number)

The number of electrons required to deposit 1 g atom of aluminium (At. Wt. = 27) from a solution of aluminium cholride will be (wher N is Avogadro's number)

The number of electrons required to deposit 1g equivalent aluminium (At. Wt. =27) from a solution of aluminium chloride will be

the number of electrons required to deposit 1g equivalent aluminium (At. Wt. =27) from a solution of aluminium chloride will be

What is the amount of electricity required to deposit one mole of aluminium from a solution of AlCl_(3) ?

The number of moles of electrons required to deposite 36 g of Al from an aqueous solution of Al(NO_(3))_(3) , is (At. wt. of Al = 27)