`(tan A+ tan B)/(cot A+ cot B)=tan A tan B`

(tan A + tan B)/( cot A + cot B)+(1- tan A tan B)/( 1- cot A cot B)=

Prove that : (cot A + tan B)/ (cot B + tan A) = cot A tan B

frac(tan A + tan B)(cot A + cot B) is equal to

Show that in a Delta ABC (cot B+cot C)/(tan B+tan C)+(cot C+cot A)/(tan C+tan A)+(cot A+cot B)/(tan A+tan B)=1

Show that (cot A + tan B) / (cot B + tan A) = cot A. tan B.

(cot A+tan B)/(cot B+tan A)=cot A tan B

Show that : (cot A+tan B)/(cot B+tan A)=cot A tan B

Prove: (cot A+tan B)/(cot B+tan A)=cot A tan B

If A, B, C, D be the angle of a quadrilateral, then (tan A + tan B + tan C + tan D)/( cot A + cot B + cot C + cot D) =

If A+B+C=180^(@) " then " sum(cot A + cot B)/(tan A + tan B)=