PQ is a vertical tower having P as the foot. A,B,C are three points in the horizontal plane through P. The angles of elevation of Q from A,B,C are equal and each is equal to `theta` . The sides of the triangle ABC are a,b,c, and area of the triangle ABC is `` . Then prove that the height of the tower is (abc) `tantheta/(4)dot`

PQ is a vertical tower having P as the foot. A,B,C are three points in the horizontal plane through P. The angles of elevation of Q from A,B,C are equal and each is equal to theta . The sides of the triangle ABC are a,b,c, and area of the triangle ABC is del . Then prove that the height of the tower is (abc) tantheta/(4)dot

PQ is a vertical tower having P as the foot. A,B,C are three points in the horizontal plane through P. The angles of elevation of Q from A,B,C are equal and each is equal to theta . The sides of the triangle ABC are a,b,c, and area of the triangle ABC is triangle . Then prove that the height of the tower is (abc) tantheta/(4 'triangle' dot

PQ is a vertical tower having P as the foot. A,B,C are three points in the horizontal plane through P. The angles of elevation of Q from A,B,C are equal and each is equal to theta . The sides of the triangle ABC are a,b,c, and area of the triangle ABC is triangle . Then prove that the height of the tower is (abc) tantheta/(4 'triangle' dot

The vertices of triangle ABC are A (4, 4), B (6, 3), C (2, -1), then angle ABC is equal to

ABC is a vertical tower such that AB=BC=x from the foot A of the tower a horizontal line AQP is drawn.If the angle of elevation of the point B from P is alpha and that of C from Q is 2 alpha then (AP)(PQ) is equal to

The angle of elevation of the top of the tower observed from each of the three points A,B,C on the ground, forming a triangle is the same angle prop . If R is the circum-radius of the triangle ABC, then the height of the tower is