The potential energy of a force filed `vec(F)` is given by `U(x,y)=sin(x+y)`. The force acting on the particle of mass m at `(0,(pi)/4)` is

The potential energy for a force filed vecF is given by U(x,y)=cos(x+y) . The force acting on a particle at position given by coordinates (0, pi//4) is

The potential energy for a force filed vecF is given by U(x,y)=cos(x+y) . The force acting on a particle at position given by coordinates (0, pi//4) is

The potential energy for a force filed vecF is given by U(x,y)=cos(x+y) . The force acting on a particle at position given by coordinates (0, pi//4) is

The potnetial energy for a force field vecF is given by U(x, y)=cos(x+y) . The force acting on a particle at the position given by coordinates (0, pi//4) is

The potential energy of a certain particle is given by U = 30x^2 - 20 y^2 . Find the force acting on the particle.

The potential energy of a body is given by U = A - Bx^(2) (where x is the displacement). The magnitude of force acting on the partical is

The potential energy of a body is given by U = A - Bx^(2) (where x is the displacement). The magnitude of force acting on the partical is

The potential energy of a conservative system is given by U= ay^(2) -by,where y represents the position of the particle and a as well b are constants.What is the force acting on the system?