" Let "f(x)={[(k cos x)/(pi-2x)," where "x=(pi)/(2)" and if "lim_(x rarr3)f(x)=f((pi)/(2))" ,find the valuedi "],[3" ,where "x=(1)/(2)]

Let f(x)={:{((kcosx)/(pi-2x)',xne(pi)/(2)),(3",",x=(pi)/(2).):} If lim_(xrarr(pi)/(2))f(x)=f((pi)/(2)), find the value of k.

f(x),={(k cos x)/(pi-2x),quad if x!=(pi)/(2) and 3,quad if x=(pi)/(2) at x,=(pi)/(2)

Let f(x)={:{((kcosx)/(pi-2x)',xne(pi)/(2)),(3",",x=(pi)/(2).):} If lim_(xto(pi)/(2))f(x)=f((pi)/(2)), find the value of k.

Let f(x)=(k cos x)/(pi-2x) if x!=(pi)/(2) and f(x=(pi)/(2)) if x=(pi)/(2) then find the value of k if lim_(x rarr(pi)/(2))f(x)=f((pi)/(2))

For f(x)=(k cos x)/(pi-2x), if x!=(pi)/(2),3, if x=(pi)/(2) then find the value of k so that f is continous at x=(pi)/(2)

Let f(x) =(kcosx)/(pi-2x) if x!=pi/2 and f(x)=3 if x=pi/2 then find the value of k if lim_(x->pi/2) f(x)=f(pi/2)

Let f(x)={(1-sin^3x)/(3cos^2x) if x pi/2 find a and b. .

f(x) = {{:((k cos x)/(pi - 2x) "if" , x ne (pi)/(2)),( 3, "if" x=(pi)/(2)):} at x= pi/2 , f (x) is containuous , find the value of k .

If f(x)={:{((cot x-cos x)/((pi-2x)^(3))", for " x != (pi)/(2)),(k ", for " x = pi/2):} is continuous at x= pi/2 , where , then k=

Find the values of k so that the function f is continuous at the indicated point. f(x)={{:((k cos x)/(pi -2x)," if "x ne (pi)/(2)),(3," if "x= (pi)/(2)):}" at "x=(pi)/(2) .