A partical is moving in a straight line under constant acceleration `4 m//s^(2)`. The motion starts from rest. Sketch v-t and s-t graph for the duration `t=0` to `t=5 s`.

A particle is moving in a straight line under acceleration a=54-18 t . The particle starts from the origin. (a) Sketch the a-t, v-t and s-t graph. (b) Find the distance traveled in the first 9 s. (Acceleration is in m//s^(2) , time is in second)

A particle is moving in a straight line under constant acceleration alpha. If the intial velocity is v_(0) , sketch the v-t and s-t graphs. (v_(0)gt0) .

A particle is moving under constant acceleration a=k t . The motion starts from rest. The velocity and displacement as a function of time t is

A particle is moving in a straight line under constant acceleration of 4 m//s^(2) . If its velocity at t=0 is 10 m//s, the displacement of particle in the 5^(th) second of its motion is

A particle, initially at rest, starts moving in a straight line with an acceleration a=6t+4 m//s^(2) . The distance covered by it in 3 s is

A particle, initially at rest, starts moving in a straight line with an acceleration a=6t+4 m//s^(2) . The distance covered by it in 3 s is

A particle is moving in a straight line and its acceleration-time graph is shown below. At t=0 , the particle is at rest. Find the velocity of the particle at t=3 s, 6 s and 8 s . Also sketch the v-s graph.

A partical is moving in a straight line such that ita velocity is given by v=t^(4)+3t^(2)+8 m//s . Find acceleration at time t=1 s .

A partical is moving in a straight line such that its displacement at any time t is given by s=4t^(3)+3t^(2) . Find the velocity and acceleration in terms of t.

A balloon starts rising with constant acceleration 2 m//s^(2) from ground at t=0s . A stone is dropped at t=5s . S-t graph for the given situation is shown in figure answer the following t_(2) is