" 1.(i) "x(x+1)(x+3)(x+4)=180

Solve : (i) x(x+1)+(x+2)(x+3)=42 (ii) (1)/(x+1)-(2)/(x+2)=(3)/(x+3)-(4)/(x+4)

If (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) and x ne 1/3 then x=? यदि (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) है तथा x ne 1/3 है, तो x=?

If i= sqrt(-1) , prove that following (x+1+ i) (x + 1- i) (x-1 + i) (x-1-i)= x^(4) + 4

Solve : (i)" "((x-1)\(x-2)(x-3))/((x+1)(x+2)(x+3))" "(ii) " "(x^(4)+x^(2)+1)/(x^(2)+4x-5)lt0

Solve : (i)" "((x-1)\(x-2)(x-3))/((x+1)(x+2)(x+3))" "(ii) " "(x^(4)+x^(2)+1)/(x^(2)+4x-5)lt0

If the normals at (x_(i),y_(i)) i=1,2,3,4 to the rectangular hyperbola xy=2 meet at the point (3,4) then (A) x_(1)+x_(2)+x_(3)+x_(4)=3 (B) y_(1)+y_(2)+y_(3)+y_(4)=4 (C) y_(1)y_(2)y_(3)y_(4)=4 (D) x_(1)x_(2)x_(3)x_(4)=-4

Solve for : x :(x-1)/(x-2)+(x-3)/(x-4)=3 1/3,x!=2,4

Solve for x : (x-1)/(x-2)+(x-3)/(x-4)=3 1/3;\ \ x!=2,\ 4

Without expanding, find the value of: (i) (x + 1)^4 - 4(x + 1)^3 (x - 1) + 6(x + 1)^2 (x - 1)^2 - 4(x + 1) (x - 1)^3 + (x -1)^4 (ii) (2x - 1)^4 + 4(2x - 1)^3 (3 - 2x) + 6(2x - 1)^2 (3 - 2x)^2 + 4(2x - 1) (3 - 2x)^3 + (3 - 2x)^4