`1p,2d` या 3f कक्षक नहीं होते , क्यों ?

If E and F are independent events, P (E) = 1/2 and P (F) = 1/3 , then P (E nn F) is :

If A={1, 2, 3}, B={a, b, c, d}, f={(1, a), (2, b), (3, d)} , then f is

Let f_(i)(x)=sin(2p_(i)x) for i=1,2,3 & p_(i) in N . If is given that the fundamental periods of f_(1)(x)+f_(2)(x)+f_(3)(x), f_(1)(x)+f_(2)(x) and f_(1)(x)+f_(3)(x) are pi, (pi)/(3) respectively, then the minimum value of p_(1)+p_(2)+p_(3) is

In Fig. 4.246, if P B C F and D P E F , then (A D)/(D E)= (FIGURE) 3/4 (b) 1/3 (c) 1/4 (d) 2/3