" (v) "(x+2)^(2)-121=0

In the following questions two equation numbered I and II are given You have to solve both equations and . . . . . (i) x-sqrt(121)=0 (ii) y^(2)-121=0

The number of zeros at the end of ( 3^(123) -3^(122) - 3^(121) ) (2^(122) - 2^(121) - 2^(120))

(x^(2)+9x-22)/(x^(2)-121) ÷ (2-x) The expression above is equivalent to

Find the no of zeros in expression: (3^(123)-3^(122)-3^121)(2^(122)-2^(121)-2^(120))

Find the no. of zeros in expression : (3^(123)-3^(122)-3^(121))(2^(121)-2^(120)-2^(119))

((32)^(0.2)+(81)^(0.25))/((256)^(0.5)-(121)^(0.5))

x- sqrt121=0, y^(2) - 121= 0

Factor the following. x^(2)+22xy+121y^(2)=0