If velocity of a particle is given by `v=(2t+3)m//s`. Then average velocity in interval `0letle1` s is :

Velocity of a particle is given by v = (3t ^(2) +2t) m/s. Find its average velocity between t = 0 to t=3s and also find its acceleration at t = 3s. Motion of the particle is in one dimension.

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

If velocity of a particle is given by v=2t^(2)-2 then find the acceleration of particle at t = 2 s.

. If the velocity of a particle is (10 + 2 t 2) m/s , then the average acceleration of the particle between 2s and 5s is

If the velocity of a particle is (10+2t^(2)m/s ,then the average acceleration of the particle between 2s and 5s is (in m/s^2)

The position of a particle moving on the x-axis is given by x=t^(3)+4t^(2)-2t+5 where x is in meter and t is in seconds (i) the velocity of the particle at t=4 s is 78 m//s (ii) the acceleration of the particle at t=4 s is 32 m//s^(2) (iii) the average velocity during the interval t=0 to t=4 s is 30 m//s (iv) the average acceleration during the interval t=0 to t=4 s is 20 m//s^(2)

Five particles have speeds 1, 2, 3, 4, 5 m/s. The average velocity of the particles is (in m/s)

The velocity of a particle is given by the equation, v = 2t^(2) + 5 cms^(-1) . Find the average acceleration during the time interval between t_(1) = 2s and t_(2) = 4s .

The positon of an object moving along x-axis is given by x(t) = (4.2 t ^(2) + 2.6) m, then find the velocity of particle at t =0s and t =3s, then find the average velocity of particle at t =0 s to t =3s.