`(sqrt(5)-2)(sqrt(3)-sqrt(5))`

rationalize the denominators (a) (1)/(sqrt(2sqrt(7)+sqrt(5))) (b) (2sqrt(5))/(sqrt(3)+sqrt(5))

Check whether (2sqrt(3)+sqrt(5))*(2sqrt(3)-sqrt(5)) is rational or irrotational? Justify your answer

Simplify (i) (3-sqrt(11))(3+sqrt(11)) (ii) (-3+ sqrt(5))(-3-sqrt(3)-sqrt(5)) (iii) (3- sqrt(3))^(2) (iv) (sqrt(5) - sqrt(3))^(2) (v) (5+ sqrt(7))(2+ sqrt(5)) (vi) (sqrt(5) - sqrt(2))(sqrt(2) - sqrt(3))

(2)/(sqrt(3)+sqrt(5))+(5)/(sqrt(3)-sqrt(5))=x sqrt(3)+y sqrt(5)

(sqrt(3)-sqrt(5))(sqrt(3)+sqrt(5))/(sqrt(7)-2sqrt(5))

((sqrt(3)+i sqrt(5))(sqrt(3)-i sqrt(5)))/((sqrt(3)+sqrt(2)i)-(sqrt(3)-i sqrt(2))

1/(sqrt(2)+sqrt(3)+sqrt(5))+1/(sqrt(2)+sqrt(3)-sqrt(5))

(1)/(sqrt(2)+sqrt(3)-sqrt(5))+(1)/(sqrt(2)-sqrt(3)-sqrt(5))

sqrt(10+2sqrt(6)+2sqrt(10)+2sqrt(15)) is equal to (sqrt(2)+sqrt(3)+sqrt(5))(sqrt(2)+sqrt(3)-sqrt(5))(c)(sqrt(2)+sqrt(5)-sqrt(3))(d) None of these

(1)/(sqrt(2)+sqrt(3))-(2)/(sqrt(5)-sqrt(3))+(3)/(sqrt(5)-sqrt(2))=