The length of one edge of a glass plate of thickness 0.2cm is 9.8cm .If this edge of the glass plate touches the surface of a liquid of surface tension 60 dyne/cm, then it is pulled down with a force of (Assume that angle of contact to be zero)

The surface tension of a liquid is 10^(8) dyne/cm .It is equivalent to

The surface tension of a liquid is 10^(8) dyne cm^(-1) . It is equivalent to

The force required to take away flat plate of radius 4cm from the surface of water is (surface tension os water =70"dyne"//cm)

If the length of the edge of a cube is 3.2 cm, then the total surface area of the cube is

Force necessary to pull a circular plate of 5cm raduis from water surface for which surface tension is 75 dynes/cm, is

If the force required to pull out a glass plate of length 9.8 cm and thickness 2 mm from a liquid is 0.6 gmwt. The surface tension of water is Nm^(-1)

The force required to take away a flat circular plate of radius 2 cm from the surface of water, will be (the surface tension of water is 70 dyne/cm)

A glass plate of length 20 cm and breadth 0.2 cm just touches the water surface in a beaker. The surface tension of water is 72 dyne/cm. The weight of the glass plate is 25 g. The weight that must be placed in the right pan to counter pose the balance is