If `A = [[1,-1,2],[3,0,-2],[1,0,3]]` prove `A.adjA=|A|I` Also,find `A^ (− 1)`

If A=[[1,-1,2],[3,0,-2],[1,0,3]] then prove that A*(adjA)=|A|I Also,find A^(-1)

If A=[[1, -1, 2], [3, 0, -2], [1, 0, 3]] , then (adjA)A=

If A=[[2, 0, -1], [3, 1, 2], [-1, 1, 2]] , then adjA=

If A=[[1, -1, 2], [-2, 3, 5], [-2, 0, -1]] , then adjA=

if A=[[1,-1,12,3,018,2,10]] then find {A(adjA)}

If A=[[1, -2, 2], [0, 2, -3], [3, -2, 4]] , then A(adjA)=

If A=[[1,0,20,2,12,0,3]], prove that A^(3)-6A^(2)+7A+2I=0

If A=[{:(1,3,3),(1,4,3),(1,3,4):}] , verify A.(adj.A)=|A|I and find A^(-1) .

[" (1) Find the adjoint of "A" ,where "A=[[1,-1,0],[2,3,-2],[2,0,1]]],[" Also verify that "A*(adj A)=|A|I_(3)" ."]

If A=[[1,-1,11,2,01,3,0]] then the value of |adjA|