Let `ABC` be a triangle with vertices `(2,2), (3,1)` ,`(5,3)`and co-ordinate of its circum-centre is `(alpha,beta)` then `alpha-beta=`

Let orthocentre of triangle ABC is H_(1) ,orthocentre of triangle BH_(1)C is H_(2) orthocentre of triangle BH_(2)C is H_(3) and so on.If A(1,1),B(1,2) and C(2,3) and co- ordinate Of H_(10) are (alpha,beta), then alpha beta is equal to

The vertices B and C of a triangle ABC lie on the lines 3y=4x and y=0 respectively and the side BC passes through the point ((2)/(3),(2)/(3)) If ABOC is a rhombus,o being the origin.If co-ordinates of vertex A is (alpha,beta), then find the value of (5)/(2)(alpha+beta)

Let A(3,4) B(5,0), C(0,5) be the vertices of a triangle ABC then orthocentre of Delta ABC is (alpha, beta) Find alpha + beta

If the centroid of a triangle with vertices (alpha, 1, 3), (-2, beta, -5) and (4, 7, gamma) is the origin then alpha beta gamma is equal to …..........

Let a, b, c be in arithmetic progression. Let the centroid of the triangle with vertices (a, e), (2, b) and (a, b) be ((10)/(3), 7/3) . If alpha, beta are the roots of the equation ax^2 + bx + 1 = 0 , then the value of alpha^2 + beta^2 - alpha beta is :

If cos^(2)alpha+cos^(2)beta=2 then tan^(3)alpha+sin^(5)beta=

If origin is the orthocentre of the triangle with vertices A(cos alpha,sin alpha),B(cos beta,sin beta),C(cos gamma,sin gamma) then cos(2 alpha-beta-gamma)+cos(2 beta-gamma-alpha)+cos(2 gamma-alpha-beta)=

If cot alpha cot beta=2 show that (cos(alpha+beta))/(cos(alpha-beta))=1/3

cos alpha+cos beta-cos(alpha+beta)=(3)/(2) then show that alpha=beta=(pi)/(3)