A normal is drawn at a point `P(x , y)` of a curve. It meets the x-axis at `Qdot` If `P Q` has constant length `k ,` then show that the differential equation describing such curves is `y(dy)/(dx)=+-sqrt(k^2-y^2)` . Find the equation of such a curve passing through `(0, k)dot`

A normal is drawn at a point P(x,y) of a curve.It meets the x-axis at Q. If PQ has constant length k, then show that the differential equation describing such curves is y(dy)/(dx)=+-sqrt(k^(2)-y^(2)). Find the equation of such a curve passing through (0,k).

A normal is drawn at a point P(x,y) of a curve It meets the x-axis at Q If PQ is of constant length k such a curve passing through (0,k) is

A normal is drawn at a point P(x,y) of a curve. It meets the x-axis at Q such that PQ is of constant length k . Answer the question:The differential equation describing such a curve is (A) y dy/dx=+-sqrt(k^2-x^2) (B) x dy/dx=+-sqrt(k^2-x^2) (C) y dy/dx=+-sqrt(k^2-y^2) (D) x dy/dx=+-sqrt(k^2-y^2)

The differential equation of the family of curves y = P(x+Q)^(2) is

Tangent drawn at any point P on a curve meets x -axis at Q such that circumcentre of Delta POQ has abscissa half that of ordinate.The differential equation to such a curve is

For the differential equation quad xy(dy)/(dx)=(x+2)(y+2) find the solution curve passing through the point

For the differential equation : xy (dy)/(dx)=(x+2)(y+2) , find the solution of curve passing through the point (1, -1).

A normal is drawn at a point P(x,y) on a curve.It meets the x-axis and thedus ofthe director such that (x intercept) ^(-1)+(y- intercept) ^(-1)=1, where O is origin,the curve passing through (3,3).