If R be a relation in a set A and `(x,y)in R rArr(y,x)in R AA x,y in A` then the relation R, is called

If a set A has a relation R and (x, y) in R implies (y, x) R AA x,y in A then the relation R is called

Let Q be the set of all rational numbers and R be the relation defined as: R={(x,y) : 1+xy gt 0, x,y in Q} Then relation R is

R is a relation on the set of N defined as R= {x, y): 2x + y = 24}. Then, the domain of R is:

Let A={0,1,2,3,4,5,6,7} ,A relation R is defined from A to A , where R= {(x,y):y=x+5,x,y in A} .Then the relation R has the range

Let R={(x,y):x^(2)+y^(2)=1,x,y in R} be a relation in R. Then the relation R is

Let N be the set of all natural numbers and we define a relation R={(x ,y):x, y in N , x+y is a multiple of 5} then the relation R is

A is a set of first 10 natural numbers and R is a relation from A to A defined as: (x,y) in R hArr x+2y=10 when x,y in A (i)Express R in the form of a set of ordered pairs. (ii) Find the domain and range of R. (iii) Find R^(-1) .

If R be a relation from set A to B defined by xRy rArr (x-y) is positive than R is. If A={4,3},B={2,3,4}