If `2hati+hatj-hatk` & `hati-4hat j+lambda hatk` are perpendicular to each other, then `lambda` is equal to

The lines barr=(2hati+hatj-3hatk)+((t)/(sqrt(6)))(2hati-hatj+hatk)andbarr=(hati+hatk)+t(4hati-hatj+lambdahatk) are perpendicular to each other, then value of lambda is

Find the value of lamda so that the two vectors 2hati+3hatj-hatk and -4hati-6hatj+lamda hatk are Perpendicular to each other

If vector vecP=a hati + a hatj +3hatk and vecQ=a hati -2 hatj -hatk are perpendicular to each other , then the positive value of a is

If the vectors 3hati+lambdahatj+hatk and 2hati-hatj+8hatk are perpendicular, then lambda is equal to

The two vectors {veca = 2hati + hatj + 3hatk, vecb = 4hati - lambda hatj + 6hatk} are parallel if lambda is equal to:

If a=2hati+2hatj+3hatk, b=-hati+2hatj+hatk and c=3hati+hatj such that a + lambda b is perpendicular to c, then the value of lambda is