.A physical quantity P=A^(3)B^(2)/CD ,If the percentage errors in the measurement of A,B,C and Dare 1%,2%,3% and 4% then what is the maximum error in the measurement of P

A physical quantity P = a^3b^2/cd . If the percentageerrors in the measurement of a, b, c and d are 1%, 2%, 3% and 4% then the percentage error in P______.

A Physical quantity P is given by P= (A^2sqrtB)/C , and the percentage errors in the measurements of A, B and C are 1% , 2 % and 4% respectively. Find the percentage error in P.

A physical quantity P is related to four observables a, b, c and d as P=a^(3)b^(2)//sqrtcd . The percentage errors in the measurements of a, b, c and d are 1%, 3% 4% and 2% respectively. What is the percentage error in the quantity P? If the value of P calculated using this formula turns out to be 3.763 , to what value should you round off the result?

In the measurement of a physical quantity x =(A sqrt(B))/(C^(2)) .The percentage error in measurement of the quantities A,B,C are 1%,2% and 2% respectively.Then the maximum possible percentage error in x is % .

A physical quantity X is given by X=(2k^(3)l^(2))/(msqrt(n)) The percentage error in the measurement of K,l,m and n are 1%,2%, 3% and 4% respectively. The value of X is uncertain by

Let x={:[(a^(2)b^(2))/(c)]:} be the physical quantity. If the percentage error in the measurement of physical quantities a,b, and c is 2,3 and 4 per cent respectively, then percentage error in the measurement of x is

A physical quantitiy X is related to four measurable quantities, a,b,c and d as give X=a^(2)b^(3)c^(5//2)d^(-2) . The percentage error in the measurement of a,b,c and d are 1%,2%,2% and 4% respectively. What is the percentage error in quantitiy X?

A physcial quantity X is related to four measurable quantites a, b, c and d as follows : X = a^2 b^3 c^(5//2) d^(-2) The percentage error in the measurement of a, b, c and d are 1% , 2%, 3% and 4%, respectively. What is the percentage error in quantity X ? if the value of X calculated on the basis of the above relation is 2.763, to what value should you round off the result ?