`x(dy)/(dx)-y=2x^(2)y`

Solve the following initial value problems : x(dy)/(dx)+2y=x^(2),y(1)=1/4

If y(x) is solution of x(dy)/(dx)+2y=x^(2),y(1)=1 then value of y((1)/(2))=

If y(x) is solution of x(dy)/(dx)+2y=x^(2), y(1)=1 then value of y(1/2)= (a) -(49)/(16) (b) (49)/(16) (c) (45)/(8) (d) -(45)/(8)

let y(x) satisfying the differential equation x(dy)/(dx)+2y=x^(2) given y(1)=1 then y(x)=

x+y(dy)/(dx) =x^(2) +y^(2)

If y=y(x) is the solution of the differential equation x(dy)/(dx)+2y=x^(2) satisfying y(1)=1 , then y(1/2) is equal to (7k)/16 . The value of k is___________________.

Solve: (y)/(x)(dy)/(dx)+(2(x^(2)+y^(2))-1)/(x^(2)+y^(2)+1)=0

Solve (x+y(dy)/(dx))/(y-x(dy)/(dx))=x^(2)+2y^(2)+(y^(4))/(x^(2))

If y=x log((x)/(a+bx)), thenx ^(3)(d^(2)y)/(dx^(2))= (a) x(dy)/(dx)-y (b) (x(dy)/(dx)-y)^(2)y(dy)/(dx)-x(d)(y(dy)/(dx)-x)^(2)

solve x(dy)/(dx)-y=sqrt(x^(2)+y^(2))