The equation of the tangent to the curve `y=sec x` at the point `(0,1)` is
(a) `y=0`
(b) `x=0`
(c) `y=1`
(d) `x=1`

Find the equation of the tangent to the curve y=sec x at the point (0,1)

Equation of the tangent to the curve y=e^(x) at (0,1) is

Equation of the tangent to the curve y= log x at (1,0) is

Where does the tangent to the curve y=e^(x) at the point (0,1) meet x-axis?

Find the equation of the tangent line to the curve y=(3x^2-1)/x at the point (1,2) is (a) 4x-y-1=0 (b) 4x+y+2=0 (c)x-y-1=0 (d) 4x-y-2=0

The equation of the tangent to the curve y=be^(-(t)/(a)) at a point,where x=0 is

The equation to the normal to the curve y=sinx at (0,\ 0) is x=0 (b) y=0 (c) x+y=0 (d) x-y=0

Find the equation of the tangent to the curve y={[x^(2)sin(1)/(x),x!=0 at the origin 0,x=0

The equation of the tangent to the curve y=be^(-x/a) at the point where it crosses the y-axis is a)(x)/(a)-(y)/(b)=1( b) ax+by=1 c)ax -by=1( d) (x)/(a)+(y)/(b)=1