यदि `(x+y)^(3)-(x-y)^(3)-6y(x^(2)-y^(2))=ky^(3)`, तो k =

Simplify: (x+y)^(3)-(x-y)^(3)-6y(x^(2)-y^(2))

Simplify : (x+y)^(3)-(x-y)^(3)-6y(x^(2)-y^(2))

Simplify: (x+y)^3-(x-y)^3-6y(x^2-y^2)

If (x+y)^3- (x-y)^3-6y (x^2-y^2)= k y^3, then k= (a)1 (b) 2 (c) 4 (d) 8

If (x+y)^3-\ (x-y)^3-6y\ (x^2-y^2)=\ k y^3, then k= (a)1 (b) 2 (c) 4 (d) 8

Simplify : (x+y)^(4) - 4y(x+y)^(3) + 6y^(2)(x+y)^(2)-4y^(3)(x+y)+y^(4)

x^(2)dx-y^(2)dy+xdx=dy-ydy-dx A) 2(x^(3)-y^(3))-3(x^(2)+y^(2))+6(x-y)=c B) 2(x^(3)-y^(3))+3(x^(2)-y^(2))+6(x+y)=c C) 2(x^(3)-y^(3))-3(x^(2)+y^(2))-6(x-y)=c D) 2(x^(3)-y^(3))+3(x^(2)+y^(2))+6(x-y)=c

If P= (x^3+y^3)/((x-y)^2+3xy), Q= ((x+y)^2-3xy)/(x^3-y^3) and R=((x+y)^2+(x-y)^2)/(x^2-y^2) , then (P div Q) xx R is equal to: यदि P= (x^3+y^3)/((x-y)^2+3xy), Q= ((x+y)^2-3xy)/(x^3-y^3) तथा R=((x+y)^2+(x-y)^2)/(x^2-y^2) है, तो (P div Q) xx R का मान क्या होगा ?

Find the centre and radius of each of the following circle : (i) x^(2)+y^(2)+4x-4y+1=0 (ii) 2x^(2)+2y^(2)-6x+6y+1=0 (iii) 2x^(2)+2y^(2)=3k(x+k) (iv) 3x^(2)+3y^(2)-5x-6y+4=0 (v) x^(2)+y^(2)-2ax-2by+a^(2)=0