Projection of line `(x+1)/2+(y+1)/(-1)=(z+3)/4` on the plane `x+2y+z=6;` has equation `x+2y+z-6=0=9x-2y-5z-8` b. `x+2y+z+6=0,9x-2y+5z=4` c. `(x-1)/4=(y-3)/(-7)=(z+1)/(10)` d. `(x+3)/4=(y-2)/7=(z-7)/(-10)`

Projection of line (x+1)/(2)+(y+1)/(-1)=(z+3)/(4) on the plane x+2y+z=6; has equation x+2y+z-6=0=9x-2y-5z-8bx+2y+z+6=0,9x-2y+5z=4c(x-1)/(4)=(y-3)/(-7)=(z+1)/(10)d.(x+3)/(4)=(y-2)/(7)=(z-7)/(-10)

Image of line (x - 2)/3 = (y - 1)/1 = (z - 1)/(-4) in the plane x + y + z = 7 is

The equation of the projection line of the line (x+1)/(2)=(y+1)/(-1)=(z+3)/(4) on the plane x+2y+z=6 is

The lines (x)/(1)=(y)/(2)=(z)/(3)and(x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

Find the equation of the projection of the line (x-1)/(2)=(y+1)/(-1)=(z-3)/(4) on the plane x+2y+z=9

The equations 2x-3y+6z=4, 5x+7y-14z=1 3x+2y-4z=0, have

Perpendiculars are drawn from points on the line (x+2)/(2)=(y+1)/(-1)=(z)/(3) to the plane x+y+z=3 The feet of perpendiculars lie on the line (a) (x)/(5)=(y-1)/(8)=(z-2)/(-13) (b) (x)/(2)=(y-1)/(3)=(z-2)/(-5)(d)(x)/(4)=(y-1)/(-7)=(z-2)/(5)(d)(x)/(2)=(y-1)/(-7)=(z-2)/(5)