How much heat is required to convert 8.0 g of ice at `-15^@` to steam at `100^@`? (Given, `c_(ice) = 0.53 cal//g-^@C, L_f = 80 cal//g and L_v = 539 cal//g, `
and `c_(water) = 1 cal//g-^@C)` .

How much heat is required to convert 8.0 g of ice at -15^@C to steam at 100^@C ? (Given, c_(ice) = 0.53 cal//g.^@C, L_f = 80 cal//g and L_v = 539 cal//g, and c_(water) = 1 cal//g.^@C) .

The amount of heat (in calories) required to convert 5g of ice at 0^(@)C to steam at 100^@C is [L_("fusion") = 80 cal g^(-1), L_("vaporization") = 540 cal g^(-1)]

The amount of heat (in calories) required to convert 5g of ice at 0^(@)C to steam at 100^@C is [L_("fusion") = 80 cal g^(-1), L_("vaporization") = 540 cal g^(-1)]

1 gram of ice at -10^@ C is converted to steam at 100^@ C the amount of heat required is (S_(ice) = 0.5 cal//g -^(@) C) (L_(v) = 536 cal//g & L_(f) = 80 cal//g,) .

Find the heat required to convert 1 g of ice at 0°0C to vapour at 100°C. (Latent heat of ice = 80 cal/g and latent heat of vapour = 536 cal/g)

What amount of ice at -14^(@)C required to cool 200gg of water from 25^(@)C to 10CC? (Given C_("ice")=0.5cal/g.^(@)C,L_(f) for ice =80cal//g )

How much work in joule is done in producing heat necessary to convert 10g of ice at -5^(@)C into steam at 100^(@)C ? Given specificheat of ice =0.5 cal g^(-1).^(@)C^(-1) , latent heat of steam = 540 cal g^(-1) .