The temperature of a body falls from `50^(@)C` to `40^(@)C` in 10 minutes. If the temperature of the surroundings is `20^(@)C` Then temperature of the body after another 10 minutes will be

The temperature of a body falls from 30^(@)C to 20^(@)C in 5 minutes. The temperature of the air is 13^(@)C . Find the temperature of the body after another 5 minutes.

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be

A body cools from 60^(@) C to 50^(@) C in 6 minutes, the temperature of the surroundings being 25^(@) C. What will be its temperature after another 6 minutes ?

The temperature of a body falls from 52^(@)C to 36^(@)C in 10 minutes when placed in a surrounding of constant temperature 20^(@)C . What will be the temperature of the body after another 10min . (Use Newton's law of cooling)

A body cools from 70^(@)C to 50^(@)C in 5 minutes. Temperature of surroundings is 20^(@)C . Its temperature after next 10 minutes is

A body cools from 70^(@)C to 50^(@)C in 6 minutes when the temperature of the surrounding is 30^(@)C . What will be the temperature of the body after further 12 minutes if coolilng proseeds ac cording to Newton's law of cooling ?

The temperature of a body falls from 40^° C to 30^° C in 10 minutes. If the temperature of surrounding is 15^° C, then time to fall the temperature from 30^° C to 20^° C

A body cools from 71^(@) C. to 50^(@) C in 5 minutes. Temperature of surroundings is 20^(@) C. Its temperature after next 10 minutes is

A body cools from 70^(@)C to 50^(@)C in 5minutes Temperature of surroundings is 20^(@)C Its temperature after next 10 minutes is .