An elevator which can carry a maximum load of `1800kg` is moving with a constant speed of `2ms^(-1)`. The frictional force opposing the motino is `5000N`. Calculate the minimum power delivered by the motor to the elevator in watt and hp ?
Take `g=10m//s^(2)`

An elevator can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a constant speed of 2 ms^(-1) . The friction force opposite the motion is 4000 N .What is minimum power delivered by the motor to the elevator?

An elevator can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a constant speed of 2 ms^(-1) . The friction force opposite the motion is 4000 N .What is minimum power delivered by the motor to the elevator?

An elevator can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a constant speed of 2ms^(-1) . The frictional force opposing the motion is 4000 N. Determine the minimum power delivered by the motor to the elevator in watts as well as in horse power.

An elevator can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a constant speed of 2ms^(-1) . The frictional force opposing the motion is 4000 N. Determine the minimum power delivered by the motor to the elevator in watts as well as in horse power.