A pump can throw up 10 quntals of coal per hour from a coal mine `120m` deep. Calculate the power of the engine in watt assuming that efficiency is `80%`.

A pump can take out 7200 kg of water per hour from a well 100 m. deep. The power of pump, assuming its efficiency as 50% will be

A pump can take out 7200 kg of water per hour from a well 100 m. deep. The power of pump, assuming its efficiency as 50% will be

An engine pumps up 1 quintal of coal from a coal mine 100 m deep in 0.5 seocnd. If its efficienty is 60% then the power of the engine is (take g=10m//s^(2))

A pump can raise 100 L of water per minute to a height of 10 m . What should be the power of the pump ?

An engine pumps 800 kg of water through height of 10 m in 80 s. Find the power of the engine if its efficiency is 75%

An engine pumps 800 kg of water through height of 10 m in 80 s. Find the power of the engine if its efficiency is 75%

A 1-KW motor pumps out water from a well 10m deep. Calculate the quantity of water pumped out per second.

A 1-KW motor pumps out water from a well 10m deep. Calculate the quantity of water pumped out per second.

An engine pumps 400 kg of water through height of 10 m in 40 s. Find the power of the engine if its efficiency is 80% (Take ,g =10 ms^(-2) ).