`[Cu(NH_(3))_(4)]^(2+)` is a square planar complex.The number of unpaired electrons and hybrid state of copper are respectively

Number of unpaired electron in Cu^(2+) is

Number of unpaired electron in Cu^(2+) is

The complex [Co(NH_(3))_(6)]^(3+) is an inner orbital complex whereas the [CoF_(6)]^(3-) is an outer orbital complex. The number of unpaired electrons in these two complexes are respectively :

[Cu(NH_(3))_(4)]^(2+) is paramagnetic and square planar complex. Justify.

In the complex ion [Cu(CN_(4))]^(3-) the hybridization state, oxidation state and number of unpaired electrons of copper are respectively

In the complex ion [Cu(CN)_4]^(3-) the hybridization state, oxidation state and number of unpaired electrons of copper are respectively.

Tetraaminecopper (II) ion is a square planar complex with one unpaired electron. According to valence bond theory the hybrid state of copper should be

The number of unpaired electrons in the square planar complex [Pt(CN)_4]^(2-) is