[" या "alpha,beta,gamma" रमाछब्र थรाि८."],[(sin alpha-sin gamma)/(cos gamma-cos alpha)=]

If alpha, beta, gamma in [0, pi]"and if" alpha, beta, gamma are in AP, then (sin alpha - sin gamma)/(cos gamma - cos alpha) is equal to

If alpha , beta , gamma in [0,pi] and if alpha , beta , gamma are in A.P then ( sin alpha - sin gamma)/( cos gamma -cos alpha) is equal to

If alpha,beta,gamma are in A.P. show that cot beta=(sin alpha-sin gamma)/(cos gamma-cos alpha)

If alpha+gamma=2beta then the expression (sin alpha-sin gamma)/(cos gamma-cos alpha) simplifies to:

If alpha+gamma=2beta then the expression (sin alpha-sin gamma)/(cos gamma-cos alpha) simplifies to:

If alpha,beta,gamma "are in A.P. show that" cot beta = (sin alpha - sin gamma)/(cos gamma -cos alpha)

cos alpha sin (beta-gamma) + cos beta sin (gamma-alpha) + cos gamma sin (alpha-beta) =

cos alpha sin (beta-gamma) + cos beta sin (gamma-alpha) + cos gamma sin (alpha-beta)=

If 0

cos alpha sin (beta-gamma)+cos beta sin (gamma-alpha) +cos gamma(sin alpha-beta)=