" 12."[(x)/(3)+1=(7)/(15)],[" Thus "(107)/(21)" should "b]

(15)/(21) of (2)/(3)-(1)/(15)=(3)/(7)

(12x + 17) / (3x + 1)-(2x + 15) / (x + 7) = 3 (1) / (5), x! =-(1) / (3), -7

Solve : (a) 1/18+1/18 (b) 8/15 + 3/15 (c) 7/5-5/7 (d) 1/22 + (21_/(22)(e) (12)/(15) -(7)/(15) (f) 5/8 + 3/8 (g) (1) - 2/3 (1=3/3) (h) 1/4 + 0/4 (i) (3) -(12)/5

Solve : (a) 1/18+1/18 (b) 8/15 + 3/15 (c) 7/5-5/7 (d) 1/22 + (21_/(22) (e) (12)/(15) -(7)/(15) (f) 5/8 + 3/8 (g) (1) - 2/3 (1=3/3) (h) 1/4 + 0/4 (i) (3) -(12)/5

Find the value of 'x' and 'y' if : 2[(x,7),(9,y-5)]+[(6,-7),(4,5)]=[(10,7),(22,15)]

5/8+3/4-7/(12) is equal to: (15)/(24) (b) (17)/(24) (c) (19)/(24) (d) (21)/(24)

Calculate the covariance of observation (3,5), (6,7),(9,9), (12,11), (15,13), (18,15), (21,17), (24, 19) using assumed mean A = 13 and B = 12.

5/8+3/4-7/(12) is equal to: (a) (15)/(24) (b) (17)/(24) (c) (19)/(24) (d) (21)/(24)

If (-3)/7=x/(35), then x= (a) 15 (b) 21 (c) -15 (d) -21