A sequence {`t_n}` is given by `t_n=n^2-1, n in N` then show that it is not an A.P

A sequence {t_(n)} is given by t_(n)=n^(2)-1,n in N, show that it is not an A.P.

A sequence {a_n} is given by : a_n=n^2-1, n in N . Show that it is not an A.P.

A sequence is given {a_n} by a_n=n^2-1, n in N show that it is not an AP.

The nth term of a sequence is given by a_(n)=2n^(2)+n+1. Show that it is not an A.P.

The nth term of a sequence is given by a_n=2n^2+n+1. Show that it is not an A.P.

The n^(th) term of a sequence is given by T_n = 2n + 7. Show that it is an A.P. Also, find its 7^(th) term.

If for a sequence (t_n) , S_n = 2n^2 + 5 , find t_n and show that the sequence is an A.P.

For a sequence, if S_n = 7 (4^n - 1) , find the t_n and show that the sequence is a G.P.

A sequence is called an A.P if the difference of a term and the previous term is always same i.e if a_(n+1)- a_(n)= constant ( common difference ) for all n in N For an A.P whose first term is 'a ' and common difference is d has n^(th) term as t_n=a+(n-1)d Sum of n terms of an A.P. whose first term is a, last term is l and common difference is d is S_(n) = n/2 (2a +(n-1)d)=n/2 (a+a+(n-1)d)= n/2 (a+l) If sum of n terms S_n for a sequence is given by S_n=An^2+Bn+C , then sequence is an A.P. whose common difference is