" 7."c^(2)+16c-36

Simplify : (2a+3b+4c) ( 4a^(2) + 9b^(2) + 16c^(2) -6ab - 12bc - 8ca )

Add : 17a^2b^2 + 16c, 28c - 28a^2b^2

If (a)/(b)=(4)/(5) and (b)/(c)=(15)/(16), then (c^(2)-a^(2))/(c^(2)+a^(2)) is (a) (1)/(7)( b) (7)/(25)( c) (3)/(4) (d) None of these

Fractorise: (2a+3b)^(2)-16c ^(2)