Line `x/a+y/b=1` cuts the co-ordinate axes at A(a,0) and B(0,b) and the line `x/a'+y/b'=-1` at `A'(-a',0)` and `B'(0,-b')`. If the points A,B,A',B' are concyclic then the orthocentre of triangle ABA' is

Line x/a+y/b=1 cuts the coordinate axes at A(a,0) and B(0,0) and the line x/a+y/b= -1 at A'(-a',0) and B'(0,-b') . If the points A,B A' ,B' are concyclic , then the orthocentre of the triangle ABA' is

Show that the points (a,0),(0,b) and (x,y) are collinear if x/a+y/b=1.

The incentre of the triangle formed by axes and the line x/a+y/b=1 is

Two point (b+3,b+k) and (2,b) are on the line x-2y+9=0 find k

The straight line (x)/(a)+(y)/(b)=1 cuts the coordinate axes at A and B .Find the equation of the circle passing through O(0,0),A and B.

The incenter of the triangle formed by the axes and the line (x)/(a)+(y)/(b)=1

The algebraic sum of distances of the line ax + by + 2 = 0 from (1,2), (2,1) and (3,5) is zero and the lines bx - ay + 4 = 0 and 3x + 4y + 5=0 cut the coordinate axes at concyclic points. Then (a) a+b=-2/7 (b) area of triangle formed by the line ax+by+2=0 with coordinate axes is 14/5 (c) line ax+by+3=0 always passes through the point (-1,1) (d) max {a,b}=5/7

8.If the lines a_(1)x+b_(1)y+c_(1)=0 and a_(2)x+b_(2)y+c_(2)=0 cuts the coordinate axes in concyclic points then