If `1/3(log)_3M+3(log)_3N=1+(log)_(0. 008)5,` then `M^9=9/N` (b) `N^9=9/M` `M^3=3/N` (d) `N^9=3/M`

If 1/3log_(3)M+3log_(3)N=1+log_(0.008)5 , then

(1)/(3)log_(3)M+3log_(3)N=1+log_(0)*0085

If (1)/(3)log_(3)M+3log_(3)N=1+log_(0.008)5, then M^(9)(9)/(N) b.N^(9)=(9)/(M) c.M^(3)=(3)/(N) d.N^(9)=(3)/(M)

((log)_(2)3)(log)_(3)4(log)_(4)5(log)_(n)(n+1)=10 Find n=?

If m;n;a>0;a!=1;log_(a)(m^(n))=n log_(a)m

Evaluate: 81^(1//log_(5)3) + 27^(log_(9)36) + 3^(4//log_(l)9)

For N>1, then product (1)/(log_(2)N)*(1)/(log_(N)8)*(1)/(log_(32)N)*(1)/(log_(N)128) simplifies to (a) (3)/(7) (b) (3)/(7ln2) (c) (3)/(5ln2)(d)(5)/(21)

Which of the following are correct? a.(log)_3 19.(log)_(1//7)3.(log)_4 1/7>2 b. (log)_5(1//23) lies between -2&-1 c. If m=4^((log)_4 7)a n d n=(1/9)^(-(log)_3 7)t h e n n=m^4 d. (log)_(sqrt(5))sin(pi/5)dot(log)_(sqrt(sin"pi"/5))5 simplifies to an irrational number