`e^(2x)-(a-1)e^x-ageq0AAx in R ,` then values of a which satisfy are. `(a) a in (-oo,0)` (b) `a in (-oo,0]` `(c) a in R` (d) `a in (-oo,2]`

f(x) = x^2 increases on: (a) ( 0,oo) (b) (-oo,0) (c) (-7,-3) (d) (-oo,-3)

f(x)=int(2-(1)/(1+x^(2))-(1)/(sqrt(1+x^(2))))dx then fis (A) increasing in (0,pi) and decreasing in (-oo,0)(B) increasing in (-oo,0) and decreasing in (0,oo)(C) increasing in (-oo,oo) and (D) decreasing in (-oo,oo)

If (|x-2|)/(x-2)geq0, then x in [2,oo) b. x in (2,oo) c. x in (-oo,2) d. x in (-oo,2]

The values of a for which the integral int_(0)^(2)|x-a|dx>=1 is satisfied are (a) (2,oo) (b) (-oo,0)(c)(0,2)(d) none of these

If (x^(2)-x)/(1-ax) attains all real values (x in R) then possible value of a are (A) (-oo , 1) (B) (1, oo) (C) [1, oo) (D)(1, 2)

If x and a are real numbers such that a>0 and |x|>a, then x in(-a,oo) b.x in[-oo,a) c.x in(-a,a) d.x in(-oo,-a)uu(a,oo)

Range of the function f(x)=(ln x)/(sqrt(x)) is (a) (-oo,\ e) (b) (-oo,\ e^2) (c) (-oo,2/e) (d) (-oo,1/e)

Let f(x)=sqrt(|x|-{x})(w h e r e{dot} denotes the fractional part of (x)a n dX , Y are its domain and range, respectively). Then (a) X in (-oo,1/2) and Y in (1/2,oo) (b)X in (-oo in ,1/2)uu[0,oo)a n dY in (1/2,oo) (c)X in (-oo,-1/2)uu[0,oo)a n dY in [0,oo) (d) none of these

The function f(x)=log x-(2x)/(x+2) is increasing for all A) x in(-oo,0) , B) x in(-oo,1) C) x in(-1,oo) D) x in(0,oo)